What is the integral of x+1/(sqrt(x)) ?

The integral of x+1/(sqrt(x)) is (x^2)/2+2sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x+1/(sqrt(x))

\int x + \frac{1}{x} d x

\frac{x ^{2}}{2} + 2 x + C

Solution steps

\int x + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int \frac{1}{x} d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{1}{x} d x = 2 x

= \frac{x ^{2}}{2} + 2 x

Add a constant to the solution

= \frac{x ^{2}}{2} + 2 x + C

\int 2 tan^{2} (2 x) sec^{2} (2 x) d x

\int 10 sin (3) x^{2} d x

\int \frac{ln ( x + 1 )}{x + x} d x

\int x cos (x) + sin (x) d x

\int (1 - \frac{1}{x ^{2}}) e^{x + \frac{1}{x}} d x

What is the integral of x+1/(sqrt(x)) ?
The integral of x+1/(sqrt(x)) is (x^2)/2+2sqrt(x)+C