What is the derivative of y=2sin(2x) ?

The derivative of y=2sin(2x) is 4cos(2x)

What is the first derivative of y=2sin(2x) ?

The first derivative of y=2sin(2x) is 4cos(2x)

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derivative of

y = 2 sin (2 x)

4 cos (2 x)

Solution steps

\frac{d}{d x} (2 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 cos (2 x) \cdot 2

Simplify

= 4 cos (2 x)

\frac{\partial}{\partial x} (x y e^{2})

\int_{1}^{3} (x + 2)^{3} d x

\int \frac{x ^{2} - x + 13}{( x + 1 ) ( x ^{2} + 4 )} d x

\int ln (X) d X

x \to 1 + lim (2 x + 5)

What is the derivative of y=2sin(2x) ?
The derivative of y=2sin(2x) is 4cos(2x)
What is the first derivative of y=2sin(2x) ?
The first derivative of y=2sin(2x) is 4cos(2x)