What is the integral of (1-ln(x))/(x^2) ?

The integral of (1-ln(x))/(x^2) is -(1-ln(x))/x+1/x+C

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integral of (1-ln(x))/(x^2)

\int \frac{1 - ln ( x )}{x ^{2}} d x

- \frac{1 - ln ( x )}{x} + \frac{1}{x} + C

Solution steps

\int \frac{1 - ln ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{1 - ln ( x )}{x} - \int \frac{1}{x ^{2}} d x

= - \frac{1 - ln ( x )}{x} - \int \frac{1}{x ^{2}} d x

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

= - \frac{1 - ln ( x )}{x} - (- \frac{1}{x})

Simplify

= - \frac{1 - ln ( x )}{x} + \frac{1}{x}

Add a constant to the solution

= - \frac{1 - ln ( x )}{x} + \frac{1}{x} + C

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What is the integral of (1-ln(x))/(x^2) ?
The integral of (1-ln(x))/(x^2) is -(1-ln(x))/x+1/x+C