What is the integral of (arctan(x))/((1+x^2)) ?

The integral of (arctan(x))/((1+x^2)) is (arctan^2(x))/2+C

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integral of (arctan(x))/((1+x^2))

\int \frac{arctan ( x )}{( 1 + x ^{2} )} d x

\frac{arctan ^{2} ( x )}{2} + C

Solution steps

\int \frac{arctan ( x )}{1 + x ^{2}} d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = arctan (x)

= \frac{arctan ^{2} ( x )}{2}

Add a constant to the solution

= \frac{arctan ^{2} ( x )}{2} + C

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What is the integral of (arctan(x))/((1+x^2)) ?
The integral of (arctan(x))/((1+x^2)) is (arctan^2(x))/2+C