What is the integral of x^{-4}sqrt(x) ?

The integral of x^{-4}sqrt(x) is -2/(5x^{5/2)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^{-4}sqrt(x)

\int x^{- 4} x d x

- \frac{2}{5 x ^{\frac{5}{2}}} + C

Solution steps

\int x^{- 4} x d x

Simplify

x^{- 4} x : \frac{1}{x ^{\frac{7}{2}}}

= \int \frac{1}{x ^{\frac{7}{2}}} d x

Apply the Power Rule

: - \frac{2}{5 x ^{\frac{5}{2}}}

= - \frac{2}{5 x ^{\frac{5}{2}}}

Add a constant to the solution

= - \frac{2}{5 x ^{\frac{5}{2}}} + C

\int \frac{x ^{2} - 1}{x - 1} d x

\int \frac{1}{e ^{2 x} + 6} d x

\int sin (x) - sin^{3} (x) d x

\int ln (3 + x) d x

\int - 10 x^{2} e^{x^{3}} d x

What is the integral of x^{-4}sqrt(x) ?
The integral of x^{-4}sqrt(x) is -2/(5x^{5/2)}+C