What is (\partial)/(\partial y)(2xyz^2) ?

The answer to (\partial)/(\partial y)(2xyz^2) is 2xz^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(2xyz^2)

\frac{\partial}{\partial y} (2 x y z^{2})

2 x z^{2}

Solution steps

\frac{\partial}{\partial y} (2 x y z^{2})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x z^{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 2 x z^{2} \cdot 1

Simplify

= 2 x z^{2}

y^{^{''}} - 4 y^{^{'}} + 4 y = 6 e^{2 t} - 6 t e^{2 t} - 12 t + 12

\int tan^{2} (2 x) sec^{4} (2 x) d x

\frac{d y}{d x} + y = \frac{1}{1 + e ^{x}}

y = (x^{3} - 9 x)^{12}, (3, 0)

\frac{\partial}{\partial x} (3 y cos (- 3 x))

What is (\partial)/(\partial y)(2xyz^2) ?
The answer to (\partial)/(\partial y)(2xyz^2) is 2xz^2