What is the integral of e^{e^x}^{e^x} ?

The integral of e^{e^x}^{e^x} is (e^{2e^{e^{e^x}}})/2+C

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integral of e^{e^x}^{e^x}

\int e^{e^{e^{e^{x}}}} d e^{e^{e^{e^{x}}}}

\frac{e ^{2 e^{e^{e^{x}}}}}{2} + C

Solution steps

\int e^{e^{e^{e^{x}}}} d e^{e^{e^{e^{x}}}}

Apply the Power Rule

: \frac{e ^{2 e^{e^{e^{x}}}}}{2}

= \frac{e ^{2 e^{e^{e^{x}}}}}{2}

Add a constant to the solution

= \frac{e ^{2 e^{e^{e^{x}}}}}{2} + C

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What is the integral of e^{e^x}^{e^x} ?
The integral of e^{e^x}^{e^x} is (e^{2e^{e^{e^x}}})/2+C