What is the integral of 10x^{2/3} ?

The integral of 10x^{2/3} is 6x^{5/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 10x^{2/3}

\int 10 x^{\frac{2}{3}} d x

6 x^{\frac{5}{3}} + C

Solution steps

\int 10 x^{\frac{2}{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int x^{\frac{2}{3}} d x

Apply the Power Rule

: \frac{3}{5} x^{\frac{5}{3}}

= 10 \cdot \frac{3}{5} x^{\frac{5}{3}}

Simplify

10 \cdot \frac{3}{5} x^{\frac{5}{3}} : 6 x^{\frac{5}{3}}

= 6 x^{\frac{5}{3}}

Add a constant to the solution

= 6 x^{\frac{5}{3}} + C

\int (5 x - 2) sin (x) d x

\int \frac{cos ^{3} ( w )}{cos ^{4} ( w )} d w

\int \frac{sin ^{5} ( x )}{cos ^{6} ( x )} d x

\int cos^{2} (3 x) sin (3 x) d x

\int x (3 - x)^{2} d x