What is the integral of 6/(x^2+8x+15) ?

The integral of 6/(x^2+8x+15) is 6(1/2 ln|x+3|-1/2 ln|x+5|)+C

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integral of 6/(x^2+8x+15)

\int \frac{6}{x ^{2} + 8 x + 15} d x

6 (\frac{1}{2} ln ∣ x + 3 ∣ - \frac{1}{2} ln ∣ x + 5 ∣) + C

Solution steps

\int \frac{6}{x ^{2} + 8 x + 15} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{1}{x ^{2} + 8 x + 15} d x

Take the partial fraction of

\frac{1}{x ^{2} + 8 x + 15} : \frac{1}{2 ( x + 3 )} - \frac{1}{2 ( x + 5 )}

= 6 \cdot \int \frac{1}{2 ( x + 3 )} - \frac{1}{2 ( x + 5 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 6 (\int \frac{1}{2 ( x + 3 )} d x - \int \frac{1}{2 ( x + 5 )} d x)

\int \frac{1}{2 ( x + 3 )} d x = \frac{1}{2} ln ∣ x + 3 ∣

\int \frac{1}{2 ( x + 5 )} d x = \frac{1}{2} ln ∣ x + 5 ∣

= 6 (\frac{1}{2} ln ∣ x + 3 ∣ - \frac{1}{2} ln ∣ x + 5 ∣)

Add a constant to the solution

= 6 (\frac{1}{2} ln ∣ x + 3 ∣ - \frac{1}{2} ln ∣ x + 5 ∣) + C

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What is the integral of 6/(x^2+8x+15) ?
The integral of 6/(x^2+8x+15) is 6(1/2 ln|x+3|-1/2 ln|x+5|)+C