What is the integral of (\sqrt[3]{x}+1)/(sqrt(x)+1) ?

The integral of (\sqrt[3]{x}+1)/(sqrt(x)+1) is

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integral of (\sqrt[3]{x}+1)/(sqrt(x)+1)

Solution steps

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int \frac{1}{x + 1} d x = 2 (x + 1 - ln x + 1)

Add a constant to the solution

\int \frac{5 x - 4}{x ^{3} + 4 x} d x

\int (x^{2} + 1)^{3} 2 x d x

\int (5 - 4 x) e^{6 - 5 x} d x

\int \frac{1}{arctan ( x ) ( 1 + x ^{2} )} d x

\int - x^{2} + 9 d x

What is the integral of (\sqrt[3]{x}+1)/(sqrt(x)+1) ?
The integral of (\sqrt[3]{x}+1)/(sqrt(x)+1) is