What is the integral of sec(1/2)y ?

The integral of sec(1/2)y is 1/2 sec(1/2)y^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sec(1/2)y

\int sec (\frac{1}{2}) y d y

\frac{1}{2} sec (\frac{1}{2}) y^{2} + C

Solution steps

\int sec (\frac{1}{2}) y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sec (\frac{1}{2}) \cdot \int y d y

Apply the Power Rule

: \frac{y ^{2}}{2}

= sec (\frac{1}{2}) \frac{y ^{2}}{2}

Simplify

sec (\frac{1}{2}) \frac{y ^{2}}{2} : \frac{1}{2} sec (\frac{1}{2}) y^{2}

= \frac{1}{2} sec (\frac{1}{2}) y^{2}

Add a constant to the solution

= \frac{1}{2} sec (\frac{1}{2}) y^{2} + C

\int (1 - x^{2})^{3} d x

\int \frac{x ^{3}}{( x + 1 )} d x

\int 9 cos^{2} (3 x) d x

\int \frac{1}{5 + cos ( x )} d x

\int \frac{x ^{3}}{x ^{2} - 3 x + 2} d x

What is the integral of sec(1/2)y ?
The integral of sec(1/2)y is 1/2 sec(1/2)y^2+C