What is the tangent of y=sin(4x) ?

The tangent of y=sin(4x) is y=cos(4a_{0})*4x+sin(4a_{0})-cos(4a_{0})*4a_{0}

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tangent of y=sin(4x)

tangent of

y = sin (4 x)

y = cos (4 a_{0}) \cdot 4 x + sin (4 a_{0}) - cos (4 a_{0}) \cdot 4 a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, sin (4 a_{0}))

Find the slope of

y = sin (4 x) : \frac{d y}{d x} = cos (4 x) \cdot 4

Compute the slope of

y = sin (4 x)

x = a_{0} : m = cos (4 a_{0}) \cdot 4

Find the line with slope m=

cos (4 a_{0}) 4

and passing through

(a_{0}, sin (4 a_{0})) : y = cos (4 a_{0}) \cdot 4 x + sin (4 a_{0}) - cos (4 a_{0}) \cdot 4 a_{0}

y = cos (4 a_{0}) \cdot 4 x + sin (4 a_{0}) - cos (4 a_{0}) \cdot 4 a_{0}

\int (cos (x))^{3} sin (x) d x

\int_{0}^{3} ((30 - y) - y^{\frac{1}{3}}) d y

\frac{d}{d x} (sin (x) - e^{x})

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (2 t), y (0) = 0, y^{^{'}} (0) = 0

\frac{d}{d r ( d )} ([\frac{12.61}{0.45} (84.4)] r (d) a d)

What is the tangent of y=sin(4x) ?
The tangent of y=sin(4x) is y=cos(4a_{0})*4x+sin(4a_{0})-cos(4a_{0})*4a_{0}