What is the integral of 1/(x^2+1) ?

The integral of 1/(x^2+1) is arctan(x)+C

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integral of 1/(x^2+1)

integral

\frac{1}{x ^{2} + 1}

arctan (x) + C

Solution steps

\int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

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