What is the integral of sec^2(x)+sin(x) ?

The integral of sec^2(x)+sin(x) is tan(x)-cos(x)+C

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integral of sec^2(x)+sin(x)

\int sec^{2} (x) + sin (x) d x

tan (x) - cos (x) + C

Solution steps

\int sec^{2} (x) + sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x + \int sin (x) d x

\int sec^{2} (x) d x = tan (x)

\int sin (x) d x = - cos (x)

= tan (x) - cos (x)

Add a constant to the solution

= tan (x) - cos (x) + C

\int \frac{ln ( 3 x )}{4 x} d x

\int x^{2} (x^{3} - 1) d x

\int \frac{cos ( ln ( x ) )}{2 x} d x

\int x [ln (x)]^{2} d x

\int (1 + \frac{1}{x})^{2} d x

What is the integral of sec^2(x)+sin(x) ?
The integral of sec^2(x)+sin(x) is tan(x)-cos(x)+C