What is the integral of x/(e^{9x)} ?

The integral of x/(e^{9x)} is -1/9 e^{-9x}x-1/81 e^{-9x}+C

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integral of x/(e^{9x)}

\int \frac{x}{e ^{9 x}} d x

- \frac{1}{9} e^{- 9 x} x - \frac{1}{81} e^{- 9 x} + C

Solution steps

\int \frac{x}{e ^{9 x}} d x

Apply Integration By Parts

: - \frac{1}{9} e^{- 9 x} x - \int - \frac{1}{9} e^{- 9 x} d x

= - \frac{1}{9} e^{- 9 x} x - \int - \frac{1}{9} e^{- 9 x} d x

\int - \frac{1}{9} e^{- 9 x} d x = \frac{1}{81} e^{- 9 x}

= - \frac{1}{9} e^{- 9 x} x - \frac{1}{81} e^{- 9 x}

Add a constant to the solution

= - \frac{1}{9} e^{- 9 x} x - \frac{1}{81} e^{- 9 x} + C

\int (48 x^{2} + 80 x) (2 x^{3} + 5 x^{2})^{\frac{3}{2}} d x

\int (2 x + 1)^{99} d x

\int (\frac{x}{x ^{2} + 1}) d x

\int \frac{x}{9} d x

What is the integral of x/(e^{9x)} ?
The integral of x/(e^{9x)} is -1/9 e^{-9x}x-1/81 e^{-9x}+C