What is the integral of x^3sqrt(5x^4-2) ?

The integral of x^3sqrt(5x^4-2) is 1/30 (5x^4-2)^{3/2}+C

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integral of x^3sqrt(5x^4-2)

\int x^{3} 5 x^{4} - 2 d x

\frac{1}{30} (5 x^{4} - 2)^{\frac{3}{2}} + C

Solution steps

\int x^{3} 5 x^{4} - 2 d x

Apply u-substitution

: \int \frac{u}{20} d u

= \int \frac{u}{20} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{20} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{20} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 5 x^{4} - 2

= \frac{1}{20} \cdot \frac{2}{3} (5 x^{4} - 2)^{\frac{3}{2}}

Simplify

\frac{1}{20} \cdot \frac{2}{3} (5 x^{4} - 2)^{\frac{3}{2}} : \frac{1}{30} (5 x^{4} - 2)^{\frac{3}{2}}

= \frac{1}{30} (5 x^{4} - 2)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{30} (5 x^{4} - 2)^{\frac{3}{2}} + C

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What is the integral of x^3sqrt(5x^4-2) ?
The integral of x^3sqrt(5x^4-2) is 1/30 (5x^4-2)^{3/2}+C