What is the integral of (2y+6)/(y+3) ?

The integral of (2y+6)/(y+3) is 2y+C

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integral of (2y+6)/(y+3)

\int \frac{2 y + 6}{y + 3} d y

2 y + C

Solution steps

\int \frac{2 y + 6}{y + 3} d y

\frac{2 y + 6}{y + 3} = 2

= \int 2 d y

Integral of a constant:

\int a d x = a x

= 2 y

Add a constant to the solution

= 2 y + C

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