What is the integral of (2x^3-5)^5x^2 ?

The integral of (2x^3-5)^5x^2 is 1/36 (2x^3-5)^6+C

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integral of (2x^3-5)^5x^2

\int (2 x^{3} - 5)^{5} x^{2} d x

\frac{1}{36} (2 x^{3} - 5)^{6} + C

Solution steps

\int (2 x^{3} - 5)^{5} x^{2} d x

Apply u-substitution

: \int \frac{u ^{5}}{6} d u

= \int \frac{u ^{5}}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int u^{5} d u

Apply the Power Rule

: \frac{u ^{6}}{6}

= \frac{1}{6} \cdot \frac{u ^{6}}{6}

Substitute back

u = 2 x^{3} - 5

= \frac{1}{6} \cdot \frac{( 2 x ^{3} - 5 ) ^{6}}{6}

Simplify

\frac{1}{6} \cdot \frac{( 2 x ^{3} - 5 ) ^{6}}{6} : \frac{1}{36} (2 x^{3} - 5)^{6}

= \frac{1}{36} (2 x^{3} - 5)^{6}

Add a constant to the solution

= \frac{1}{36} (2 x^{3} - 5)^{6} + C

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What is the integral of (2x^3-5)^5x^2 ?
The integral of (2x^3-5)^5x^2 is 1/36 (2x^3-5)^6+C