What is the integral of (2x^2+3)/(x^2(x-1)) ?

The integral of (2x^2+3)/(x^2(x-1)) is -3ln|x|+3/x+5ln|x-1|+C

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integral of (2x^2+3)/(x^2(x-1))

\int \frac{2 x ^{2} + 3}{x ^{2} ( x - 1 )} d x

- 3 ln ∣ x ∣ + \frac{3}{x} + 5 ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{2 x ^{2} + 3}{x ^{2} ( x - 1 )} d x

Take the partial fraction of

\frac{2 x ^{2} + 3}{x ^{2} ( x - 1 )} : - \frac{3}{x} - \frac{3}{x ^{2}} + \frac{5}{x - 1}

= \int - \frac{3}{x} - \frac{3}{x ^{2}} + \frac{5}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{3}{x} d x - \int \frac{3}{x ^{2}} d x + \int \frac{5}{x - 1} d x

\int \frac{3}{x} d x = 3 ln ∣ x ∣

\int \frac{3}{x ^{2}} d x = - \frac{3}{x}

\int \frac{5}{x - 1} d x = 5 ln ∣ x - 1 ∣

= - 3 ln ∣ x ∣ - (- \frac{3}{x}) + 5 ln ∣ x - 1 ∣

Simplify

= - 3 ln ∣ x ∣ + \frac{3}{x} + 5 ln ∣ x - 1 ∣

Add a constant to the solution

= - 3 ln ∣ x ∣ + \frac{3}{x} + 5 ln ∣ x - 1 ∣ + C

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What is the integral of (2x^2+3)/(x^2(x-1)) ?
The integral of (2x^2+3)/(x^2(x-1)) is -3ln|x|+3/x+5ln|x-1|+C