What is the integral of (x^3-10x+3) ?

The integral of (x^3-10x+3) is (x^4)/4-5x^2+3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^3-10x+3)

\int (x^{3} - 10 x + 3) d x

\frac{x ^{4}}{4} - 5 x^{2} + 3 x + C

Solution steps

\int x^{3} - 10 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 10 x d x + \int 3 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 10 x d x = 5 x^{2}

\int 3 d x = 3 x

= \frac{x ^{4}}{4} - 5 x^{2} + 3 x

Add a constant to the solution

= \frac{x ^{4}}{4} - 5 x^{2} + 3 x + C

\int \frac{x - 4}{4 x ^{2} - 32 x - 1} d x

\int \frac{3 + ln ( x )}{x} d x

\int \frac{x ^{2} + 4 x + 1}{( x - 1 ) ( x + 1 ) ( x + 3 )} d x

\int \frac{1}{x + 1 + 1} d x

\int \frac{ln ( x ) + 1}{x ^{x} - 1} d x

What is the integral of (x^3-10x+3) ?
The integral of (x^3-10x+3) is (x^4)/4-5x^2+3x+C