What is the integral of cos(2x)sin^3(2x) ?

The integral of cos(2x)sin^3(2x) is 1/8 sin^4(2x)+C

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integral of cos(2x)sin^3(2x)

\int cos (2 x) sin^{3} (2 x) d x

\frac{1}{8} sin^{4} (2 x) + C

Solution steps

\int cos (2 x) sin^{3} (2 x) d x

Apply u-substitution

: \int \frac{3 u}{6} d u

= \int \frac{3 u}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int 3 u d u

Apply the Power Rule

: \frac{3}{4} u^{\frac{4}{3}}

= \frac{1}{6} \cdot \frac{3}{4} u^{\frac{4}{3}}

Substitute back

u = sin^{3} (2 x)

= \frac{1}{6} \cdot \frac{3}{4} (sin^{3} (2 x))^{\frac{4}{3}}

Simplify

\frac{1}{6} \cdot \frac{3}{4} (sin^{3} (2 x))^{\frac{4}{3}} : \frac{1}{8} sin^{4} (2 x)

= \frac{1}{8} sin^{4} (2 x)

Add a constant to the solution

= \frac{1}{8} sin^{4} (2 x) + C

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What is the integral of cos(2x)sin^3(2x) ?
The integral of cos(2x)sin^3(2x) is 1/8 sin^4(2x)+C