What is the integral of cos(x^2)6x ?

The integral of cos(x^2)6x is 3sin(x^2)+C

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integral of cos(x^2)6x

\int cos (x^{2}) 6 x d x

3 sin (x^{2}) + C

Solution steps

\int cos (x^{2}) \cdot 6 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int cos (x^{2}) x d x

Apply u-substitution

: \int \frac{cos ( u )}{2} d u

= 6 \cdot \int \frac{cos ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 6 \cdot \frac{1}{2} sin (u)

Substitute back

u = x^{2}

= 6 \cdot \frac{1}{2} sin (x^{2})

Simplify

6 \cdot \frac{1}{2} sin (x^{2}) : 3 sin (x^{2})

= 3 sin (x^{2})

Add a constant to the solution

= 3 sin (x^{2}) + C

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