What is the integral of 1/(\sqrt[3]{z^2)} ?

The integral of 1/(\sqrt[3]{z^2)} is 3\sqrt[3]{z}+C

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integral of 1/(\sqrt[3]{z^2)}

Solution steps

assuming

z \geq 0

= \int \frac{1}{z ^{\frac{2}{3}}} d z

Apply the Power Rule

: 3 z^{\frac{1}{3}}

= 3 z^{\frac{1}{3}}

Apply radical rule:

Add a constant to the solution

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What is the integral of 1/(\sqrt[3]{z^2)} ?
The integral of 1/(\sqrt[3]{z^2)} is 3\sqrt[3]{z}+C