What is the integral of (x^3+2x-4) ?

The integral of (x^3+2x-4) is (x^4)/4+x^2-4x+C

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integral of (x^3+2x-4)

\int (x^{3} + 2 x - 4) d x

\frac{x ^{4}}{4} + x^{2} - 4 x + C

Solution steps

\int x^{3} + 2 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int 2 x d x - \int 4 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 2 x d x = x^{2}

\int 4 d x = 4 x

= \frac{x ^{4}}{4} + x^{2} - 4 x

Add a constant to the solution

= \frac{x ^{4}}{4} + x^{2} - 4 x + C

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What is the integral of (x^3+2x-4) ?
The integral of (x^3+2x-4) is (x^4)/4+x^2-4x+C