What is the derivative of y=(4x-1)^3 ?

The derivative of y=(4x-1)^3 is 12(4x-1)^2

What is the first derivative of y=(4x-1)^3 ?

The first derivative of y=(4x-1)^3 is 12(4x-1)^2

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derivative of

y = (4 x - 1)^{3}

12 (4 x - 1)^{2}

Solution steps

\frac{d}{d x} ((4 x - 1)^{3})

Apply the chain rule:

3 (4 x - 1)^{2} \frac{d}{d x} (4 x - 1)

= 3 (4 x - 1)^{2} \frac{d}{d x} (4 x - 1)

\frac{d}{d x} (4 x - 1) = 4

= 3 (4 x - 1)^{2} \cdot 4

Simplify

= 12 (4 x - 1)^{2}

y = 7 x - x^{2}, at x = 1

f (x) = 3^{c o s (x)}

\int tan (x) d x

\frac{d}{d x} (\frac{1 - e ^{x}}{1 + e ^{x}})

(ln (x^{'}))^{^{'}}

What is the derivative of y=(4x-1)^3 ?
The derivative of y=(4x-1)^3 is 12(4x-1)^2
What is the first derivative of y=(4x-1)^3 ?
The first derivative of y=(4x-1)^3 is 12(4x-1)^2