What is the integral of (ln(x))/(x^2) ?

The integral of (ln(x))/(x^2) is -(ln(x))/x-1/x+C

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integral of (ln(x))/(x^2)

integral

\frac{ln ( x )}{x ^{2}}

- \frac{ln ( x )}{x} - \frac{1}{x} + C

Solution steps

\int \frac{ln ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

= - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

\int - \frac{1}{x ^{2}} d x = \frac{1}{x}

= - \frac{ln ( x )}{x} - \frac{1}{x}

Add a constant to the solution

= - \frac{ln ( x )}{x} - \frac{1}{x} + C

x ln (x)

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What is the integral of (ln(x))/(x^2) ?
The integral of (ln(x))/(x^2) is -(ln(x))/x-1/x+C