What is the integral of (x)^{-1/2} ?

The integral of (x)^{-1/2} is 2x^{1/2}+C

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integral of (x)^{-1/2}

\int (x)^{- \frac{1}{2}} d x

2 x^{\frac{1}{2}} + C

Solution steps

\int x^{- \frac{1}{2}} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 x^{\frac{1}{2}}

Add a constant to the solution

= 2 x^{\frac{1}{2}} + C

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