What is the tangent of y=5x-x^2,(1,4) ?

The tangent of y=5x-x^2,(1,4) is y=3x+1

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tangent of y=5x-x^2,(1,4)

tangent of

y = 5 x - x^{2}, (1, 4)

y = 3 x + 1

Solution steps

Find the slope of

y = 5 x - x^{2} : \frac{d y}{d x} = 5 - 2 x

Compute the slope of

y = 5 x - x^{2}

(1, 4) : m = 3

Find the line with slope m=

3

and passing through

(1, 4) : y = 3 x + 1

y = 3 x + 1

y \to 1 lim (\frac{y ^{2} + 3}{y - 1})

\int (8 e^{2} x) - (3 e^{- x}) d x

\frac{d}{d x} ((2 - 2 x)^{2} (3 x + 1)^{2})

\frac{d}{d x} (\frac{a + b x}{c + d x})

3 t e^{- 2 t}