What is the integral of 1/((cos^2(x))) ?

The integral of 1/((cos^2(x))) is tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((cos^2(x)))

\int \frac{1}{( cos ^{2} ( x ) )} d x

tan (x) + C

Solution steps

\int \frac{1}{cos ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{cos ^{2} ( x )} d x = tan (x)

= tan (x)

Add a constant to the solution

= tan (x) + C

\int \frac{4 x ^{2}}{x ^{2} + 1} d x

\int x (8 x)^{\frac{3}{2}} + 7 d x

\int (\frac{x ^{2}}{2}) d x

\int 7 x - x^{2} d x

\int - \frac{200 x}{( 14 + \frac{1}{2} x ^{2} ) ^{\frac{3}{2}}} d x

What is the integral of 1/((cos^2(x))) ?
The integral of 1/((cos^2(x))) is tan(x)+C