What is the integral of (x+1)/(sqrt(x^2+2x-4)) ?

The integral of (x+1)/(sqrt(x^2+2x-4)) is sqrt(x^2+2x-4)+C

Popular >

integral of (x+1)/(sqrt(x^2+2x-4))

\int \frac{x + 1}{x ^{2} + 2 x - 4} d x

x^{2} + 2 x - 4 + C

Solution steps

\int \frac{x + 1}{x ^{2} + 2 x - 4} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= \frac{1}{2} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = x^{2} + 2 x - 4

= \frac{1}{2} \cdot 2 (x^{2} + 2 x - 4)^{\frac{1}{2}}

Simplify

\frac{1}{2} \cdot 2 (x^{2} + 2 x - 4)^{\frac{1}{2}} : x^{2} + 2 x - 4

= x^{2} + 2 x - 4

Add a constant to the solution

= x^{2} + 2 x - 4 + C

\int \frac{1}{( x ^{2} + a ^{2} ) ^{3}} d x

\int \frac{1}{x x ^{2} + 2} d x

\int \frac{e ^{3 x}}{e ^{3 x} - 4} d x

\int \frac{x ^{4} + x + 4}{x ^{2} + 2} d x

4^{x}

What is the integral of (x+1)/(sqrt(x^2+2x-4)) ?
The integral of (x+1)/(sqrt(x^2+2x-4)) is sqrt(x^2+2x-4)+C