What is the derivative of 3(x-1^2) ?

The derivative of 3(x-1^2) is 6(x-1)

What is the first derivative of 3(x-1^2) ?

The first derivative of 3(x-1^2) is 6(x-1)

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\frac{d}{d x} (3 (x - 1)^{2})

6 (x - 1)

Solution steps

\frac{d}{d x} (3 (x - 1)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} ((x - 1)^{2})

Apply the chain rule:

2 (x - 1) \frac{d}{d x} (x - 1)

= 2 (x - 1) \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 3 \cdot 2 (x - 1) \cdot 1

Simplify

= 6 (x - 1)

\int \frac{1}{sin ^{4} ( x )} d x

\frac{d}{d x} (z (x) + x^{2})

\int_{0}^{1} t 1 + t^{2} + t^{4} d t

x \to 3 - lim (sin (π x) + 1)

\int e^{2 x + e^{x}} d x

What is the derivative of 3(x-1^2) ?
The derivative of 3(x-1^2) is 6(x-1)
What is the first derivative of 3(x-1^2) ?
The first derivative of 3(x-1^2) is 6(x-1)