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Popular >

integral of 1/(v+1)

Solution

\int \frac{1}{v + 1} d v

Solution

ln ∣ v + 1 ∣ + C

Solution steps

\int \frac{1}{v + 1} d v

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = v + 1

= ln ∣ v + 1 ∣

Add a constant to the solution

= ln ∣ v + 1 ∣ + C

Graph

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\int x 9 x + 2 d x

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\int \frac{x + 1}{x + 1} d x

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\int \frac{sin ( 2 x )}{3 + cos ^{2} ( x )} d x

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\int x^{(- \frac{1}{2})} d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(v+1) ?
The integral of 1/(v+1) is ln|v+1|+C