What is the integral of-cos(x)e^x ?

The integral of-cos(x)e^x is -(e^xsin(x))/2-(e^xcos(x))/2+C

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integral of-cos(x)e^x

\int - cos (x) e^{x} d x

- \frac{e ^{x} sin ( x )}{2} - \frac{e ^{x} cos ( x )}{2} + C

Solution steps

\int - cos (x) e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int cos (x) e^{x} d x

Apply Integration By Parts

: e^{x} sin (x) - \int e^{x} sin (x) d x

= - (e^{x} sin (x) - \int e^{x} sin (x) d x)

Apply Integration By Parts

: - e^{x} cos (x) - \int - e^{x} cos (x) d x

= - (e^{x} sin (x) - (- e^{x} cos (x) - \int - e^{x} cos (x) d x))

Therefore

\int - e^{x} cos (x) d x = - (e^{x} sin (x) - (- e^{x} cos (x) - \int - e^{x} cos (x) d x))

Isolate

\int - e^{x} cos (x) d x

= - \frac{e ^{x} sin ( x )}{2} - \frac{e ^{x} cos ( x )}{2}

Add a constant to the solution

= - \frac{e ^{x} sin ( x )}{2} - \frac{e ^{x} cos ( x )}{2} + C

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What is the integral of-cos(x)e^x ?
The integral of-cos(x)e^x is -(e^xsin(x))/2-(e^xcos(x))/2+C