What is the integral of 2e^x-3cos(x) ?

The integral of 2e^x-3cos(x) is 2e^x-3sin(x)+C

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integral of 2e^x-3cos(x)

\int 2 e^{x} - 3 cos (x) d x

2 e^{x} - 3 sin (x) + C

Solution steps

\int 2 e^{x} - 3 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 e^{x} d x - \int 3 cos (x) d x

\int 2 e^{x} d x = 2 e^{x}

\int 3 cos (x) d x = 3 sin (x)

= 2 e^{x} - 3 sin (x)

Add a constant to the solution

= 2 e^{x} - 3 sin (x) + C

\int (e^{x} - 3 cos (x)) d x

\int \frac{3 x + 1}{x ^{2} - 4 x + 3} d x

\int \frac{5}{x ^{3}} d x

\int x 9 x + 4 d x

\int 9 x - x^{2} d x

What is the integral of 2e^x-3cos(x) ?
The integral of 2e^x-3cos(x) is 2e^x-3sin(x)+C