What is the integral of (x^3+x^2)/(x+2) ?

The integral of (x^3+x^2)/(x+2) is -3x^2-4x+1/3 (x+2)^3+1/2 (x+2)^2-4ln|x+2|+4+C

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integral of (x^3+x^2)/(x+2)

\int \frac{x ^{3} + x ^{2}}{x + 2} d x

- 3 x^{2} - 4 x + \frac{1}{3} (x + 2)^{3} + \frac{1}{2} (x + 2)^{2} - 4 ln ∣ x + 2 ∣ + 4 + C

Solution steps

\int \frac{x ^{3} + x ^{2}}{x + 2} d x

Expand

\frac{x ^{3} + x ^{2}}{x + 2} : \frac{x ^{3}}{x + 2} + \frac{x ^{2}}{x + 2}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{3}}{x + 2} d x + \int \frac{x ^{2}}{x + 2} d x

\int \frac{x ^{3}}{x + 2} d x = - 3 x^{2} + \frac{1}{3} (x + 2)^{3} - 8 ln ∣ x + 2 ∣ + 12

\int \frac{x ^{2}}{x + 2} d x = \frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 4 ln ∣ x + 2 ∣

= - 3 x^{2} + \frac{1}{3} (x + 2)^{3} - 8 ln ∣ x + 2 ∣ + 12 + \frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 4 ln ∣ x + 2 ∣

Simplify

- 3 x^{2} + \frac{1}{3} (x + 2)^{3} - 8 ln ∣ x + 2 ∣ + 12 + \frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 4 ln ∣ x + 2 ∣ : - 3 x^{2} - 4 x + \frac{1}{3} (x + 2)^{3} + \frac{1}{2} (x + 2)^{2} - 4 ln ∣ x + 2 ∣ + 4

= - 3 x^{2} - 4 x + \frac{1}{3} (x + 2)^{3} + \frac{1}{2} (x + 2)^{2} - 4 ln ∣ x + 2 ∣ + 4

Add a constant to the solution

= - 3 x^{2} - 4 x + \frac{1}{3} (x + 2)^{3} + \frac{1}{2} (x + 2)^{2} - 4 ln ∣ x + 2 ∣ + 4 + C

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What is the integral of (x^3+x^2)/(x+2) ?
The integral of (x^3+x^2)/(x+2) is -3x^2-4x+1/3 (x+2)^3+1/2 (x+2)^2-4ln|x+2|+4+C