What is the tangent of y=g(x),\at x=6 ?

The tangent of y=g(x),\at x=6 is y= d/(d6)(g(6))x+g(6)-d/(d6)(g(6))6

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tangent of y=g(x),\at x=6

tangent of

y = g (x), at x = 6

y = \frac{d}{d 6} (g (6)) x + g (6) - \frac{d}{d 6} (g (6)) 6

Solution steps

Find the tangent point:

(6, g (6))

Find the slope of

y = g (x) : \frac{d y}{d x} = \frac{d g}{d x}

Compute the slope of

y = g (x)

x = 6 : m = \frac{d}{d 6} (g (6))

Find the line with slope m=

\frac{d}{d 6} (g (6))

and passing through

(6, g (6)) : y = \frac{d}{d 6} (g (6)) x + g (6) - \frac{d}{d 6} (g (6)) 6

y = \frac{d}{d 6} (g (6)) x + g (6) - \frac{d}{d 6} (g (6)) 6

\frac{3}{s \cdot ( s ^{2} + 2 s + 5 )}

\int_{0}^{2 π} cos (x) cos (2 x) d x

\int sin^{3} (x) cos^{8} (x) d x

\int (x^{2} - 3)^{2} (2 x) d x

x \to 0 + lim (\frac{1}{3 x})

What is the tangent of y=g(x),\at x=6 ?
The tangent of y=g(x),\at x=6 is y= d/(d6)(g(6))x+g(6)-d/(d6)(g(6))6