What is the integral of x^2cos(2x+1) ?

The integral of x^2cos(2x+1) is 1/2 x^2sin(2x+1)+1/2 xcos(2x+1)-1/4 sin(2x+1)+C

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integral of x^2cos(2x+1)

\int x^{2} cos (2 x + 1) d x

\frac{1}{2} x^{2} sin (2 x + 1) + \frac{1}{2} x cos (2 x + 1) - \frac{1}{4} sin (2 x + 1) + C

Solution steps

\int x^{2} cos (2 x + 1) d x

Apply Integration By Parts

: \frac{1}{2} x^{2} sin (2 x + 1) - \int x sin (2 x + 1) d x

= \frac{1}{2} x^{2} sin (2 x + 1) - \int x sin (2 x + 1) d x

\int x sin (2 x + 1) d x = - \frac{1}{2} x cos (2 x + 1) + \frac{1}{4} sin (2 x + 1)

= \frac{1}{2} x^{2} sin (2 x + 1) - (- \frac{1}{2} x cos (2 x + 1) + \frac{1}{4} sin (2 x + 1))

Simplify

= \frac{1}{2} x^{2} sin (2 x + 1) + \frac{1}{2} x cos (2 x + 1) - \frac{1}{4} sin (2 x + 1)

Add a constant to the solution

= \frac{1}{2} x^{2} sin (2 x + 1) + \frac{1}{2} x cos (2 x + 1) - \frac{1}{4} sin (2 x + 1) + C

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What is the integral of x^2cos(2x+1) ?
The integral of x^2cos(2x+1) is 1/2 x^2sin(2x+1)+1/2 xcos(2x+1)-1/4 sin(2x+1)+C