What is the derivative of f(x)= 1/(cos(x)) ?

The derivative of f(x)= 1/(cos(x)) is sec(x)tan(x)

What is the first derivative of f(x)= 1/(cos(x)) ?

The first derivative of f(x)= 1/(cos(x)) is sec(x)tan(x)

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derivative of

f (x) = \frac{1}{cos ( x )}

sec (x) tan (x)

Solution steps

\frac{d}{d x} (\frac{1}{cos ( x )})

Simplify

\frac{1}{cos ( x )} : sec (x)

= \frac{d}{d x} (sec (x))

Apply the common derivative:

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= sec (x) tan (x)

\frac{d}{d y} (2 x y^{4} e^{y} + 2 x y^{3} + y)

y^{^{''}} + 4 y^{^{'}} + 6 y = cos (x), y (0) = 0, y^{^{'}} (0) = 2

n = 1 \sum \infty \frac{x ^{n}}{2 n - 1}

\frac{\partial}{\partial x} (e^{x z})

x \to 0 + lim ((1 - 4 x)^{\frac{1}{x}})

What is the derivative of f(x)= 1/(cos(x)) ?
The derivative of f(x)= 1/(cos(x)) is sec(x)tan(x)
What is the first derivative of f(x)= 1/(cos(x)) ?
The first derivative of f(x)= 1/(cos(x)) is sec(x)tan(x)