What is the integral of sqrt(\sqrt{\sqrt{x)}} ?

The integral of sqrt(\sqrt{\sqrt{x)}} is 8/9 x^{9/8}+C

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integral of sqrt(\sqrt{\sqrt{x)}}

\int x d x

\frac{8}{9} x^{\frac{9}{8}} + C

Solution steps

\int x d x

Simplify

Apply the Power Rule

: \frac{8}{9} x^{\frac{9}{8}}

= \frac{8}{9} x^{\frac{9}{8}}

Add a constant to the solution

= \frac{8}{9} x^{\frac{9}{8}} + C

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What is the integral of sqrt(\sqrt{\sqrt{x)}} ?
The integral of sqrt(\sqrt{\sqrt{x)}} is 8/9 x^{9/8}+C