What is the integral of (cos^5(a))/(sqrt(sin(a))) ?

The integral of (cos^5(a))/(sqrt(sin(a))) is 2sqrt(sin(a))-4/5 sin^{5/2}(a)+2/9 sin^{9/2}(a)+C

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integral of (cos^5(a))/(sqrt(sin(a)))

\int \frac{cos ^{5} ( a )}{sin ( a )} d a

2 sin (a) - \frac{4}{5} sin^{\frac{5}{2}} (a) + \frac{2}{9} sin^{\frac{9}{2}} (a) + C

Solution steps

\int \frac{cos ^{5} ( a )}{sin ( a )} d a

Rewrite using trig identities

= \int \frac{( 1 - sin ^{2} ( a ) ) ^{2} cos ( a )}{sin ( a )} d a

Apply u-substitution

: \int \frac{( 1 - u ^{2} ) ^{2}}{u} d u

= \int \frac{( 1 - u ^{2} ) ^{2}}{u} d u

Expand

\frac{( 1 - u ^{2} ) ^{2}}{u} : \frac{1}{u} - 2 u^{\frac{3}{2}} + u^{\frac{7}{2}}

= \int \frac{1}{u} - 2 u^{\frac{3}{2}} + u^{\frac{7}{2}} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{u} d u - \int 2 u^{\frac{3}{2}} d u + \int u^{\frac{7}{2}} d u

\int \frac{1}{u} d u = 2 u

\int 2 u^{\frac{3}{2}} d u = \frac{4}{5} u^{\frac{5}{2}}

\int u^{\frac{7}{2}} d u = \frac{2}{9} u^{\frac{9}{2}}

= 2 u - \frac{4}{5} u^{\frac{5}{2}} + \frac{2}{9} u^{\frac{9}{2}}

Substitute back

u = sin (a)

= 2 sin (a) - \frac{4}{5} sin^{\frac{5}{2}} (a) + \frac{2}{9} sin^{\frac{9}{2}} (a)

Add a constant to the solution

= 2 sin (a) - \frac{4}{5} sin^{\frac{5}{2}} (a) + \frac{2}{9} sin^{\frac{9}{2}} (a) + C

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What is the integral of (cos^5(a))/(sqrt(sin(a))) ?
The integral of (cos^5(a))/(sqrt(sin(a))) is 2sqrt(sin(a))-4/5 sin^{5/2}(a)+2/9 sin^{9/2}(a)+C