What is the integral of (1/2-1/2 cos(2x)) ?

The integral of (1/2-1/2 cos(2x)) is 1/2 x-1/4 sin(2x)+C

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integral of (1/2-1/2 cos(2x))

\int (\frac{1}{2} - \frac{1}{2} cos (2 x)) d x

\frac{1}{2} x - \frac{1}{4} sin (2 x) + C

Solution steps

\int \frac{1}{2} - \frac{1}{2} cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{2} d x - \int \frac{1}{2} cos (2 x) d x

\int \frac{1}{2} d x = \frac{1}{2} x

\int \frac{1}{2} cos (2 x) d x = \frac{1}{4} sin (2 x)

= \frac{1}{2} x - \frac{1}{4} sin (2 x)

Add a constant to the solution

= \frac{1}{2} x - \frac{1}{4} sin (2 x) + C

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What is the integral of (1/2-1/2 cos(2x)) ?
The integral of (1/2-1/2 cos(2x)) is 1/2 x-1/4 sin(2x)+C