What is area y=1.2(x+0.1)^{0.5}+4,1,-0.1 ?

The answer to area y=1.2(x+0.1)^{0.5}+4,1,-0.1 is 5.32295…

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area y=1.2(x+0.1)^{0.5}+4,1,-0.1

area

y = 1.2 (x + 0.1)^{0.5} + 4, 1, - 0.1

5.32295 \dots

Solution steps

Apply the area formula:

\int_{- 0.1}^{1} 1.2 (x + 0.1)^{0.5} + 4 d x

Solve

\int_{- 0.1}^{1} 1.2 (x + 0.1)^{0.5} + 4 d x : 5.32295 \dots

The area is:

= 5.32295 \dots

n = 0 \sum \infty 2^{n} 2^{n}

\frac{\partial}{\partial z} (x^{2} y^{2} z^{2})

x^{2} - 3 x + 6, at x = 1

\frac{d}{d x} (7 x^{2} - \frac{3}{x} + 2 x)

\frac{d}{d x} (\frac{x - 3}{x + 3})

What is area y=1.2(x+0.1)^{0.5}+4,1,-0.1 ?
The answer to area y=1.2(x+0.1)^{0.5}+4,1,-0.1 is 5.32295…