What is (\partial)/(\partial z)(x^2y^2z^2) ?

The answer to (\partial)/(\partial z)(x^2y^2z^2) is 2x^2y^2z

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(\partial)/(\partial z)(x^2y^2z^2)

\frac{\partial}{\partial z} (x^{2} y^{2} z^{2})

2 x^{2} y^{2} z

Solution steps

\frac{\partial}{\partial z} (x^{2} y^{2} z^{2})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} y^{2} \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{2} y^{2} \cdot 2 z^{2 - 1}

Simplify

= 2 x^{2} y^{2} z

x^{2} - 3 x + 6, at x = 1

\frac{d}{d x} (7 x^{2} - \frac{3}{x} + 2 x)

\frac{d}{d x} (\frac{x - 3}{x + 3})

x^{2} + 7

\int x^{2} 2 x - 1 d x

What is (\partial)/(\partial z)(x^2y^2z^2) ?
The answer to (\partial)/(\partial z)(x^2y^2z^2) is 2x^2y^2z