What is the integral of x^3+1/(x^5) ?

The integral of x^3+1/(x^5) is (x^4)/4-1/(4x^4)+C

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integral of x^3+1/(x^5)

\int x^{3} + \frac{1}{x ^{5}} d x

\frac{x ^{4}}{4} - \frac{1}{4 x ^{4}} + C

Solution steps

\int x^{3} + \frac{1}{x ^{5}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int \frac{1}{x ^{5}} d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int \frac{1}{x ^{5}} d x = - \frac{1}{4 x ^{4}}

= \frac{x ^{4}}{4} - \frac{1}{4 x ^{4}}

Add a constant to the solution

= \frac{x ^{4}}{4} - \frac{1}{4 x ^{4}} + C

\int - t sin (t) d t

\int \frac{x + 1}{1 + 1 + x} d x

\int \frac{1}{x} + \frac{1}{x ^{2}} d x

\int (16 x^{3} + 6) (2 x^{4} + 3 x)^{19} d x

\frac{1}{( x - 1 ) ^{2}}

What is the integral of x^3+1/(x^5) ?
The integral of x^3+1/(x^5) is (x^4)/4-1/(4x^4)+C