What is the derivative of (6e^w)/(7w) ?

The derivative of (6e^w)/(7w) is (6(e^ww-e^w))/(7w^2)

What is the first derivative of (6e^w)/(7w) ?

The first derivative of (6e^w)/(7w) is (6(e^ww-e^w))/(7w^2)

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derivative of

\frac{6 e ^{w}}{7 w}

\frac{6 ( e ^{w} w - e ^{w} )}{7 w ^{2}}

Solution steps

\frac{d}{d w} (\frac{6 e ^{w}}{7 w})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{6}{7} \frac{d}{d w} (\frac{e ^{w}}{w})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{6}{7} \cdot \frac{\frac{d}{d w} ( e ^{w} ) w - \frac{d w}{d w} e ^{w}}{w ^{2}}

\frac{d}{d w} (e^{w}) = e^{w}

\frac{d w}{d w} = 1

= \frac{6}{7} \cdot \frac{e ^{w} w - 1 \cdot e ^{w}}{w ^{2}}

Simplify

\frac{6}{7} \cdot \frac{e ^{w} w - 1 \cdot e ^{w}}{w ^{2}} : \frac{6 ( e ^{w} w - e ^{w} )}{7 w ^{2}}

= \frac{6 ( e ^{w} w - e ^{w} )}{7 w ^{2}}

\frac{d}{d x} (1 4^{2 x})

\frac{5 u}{4 u ^{2} + 1}

f (x) = x + 2, at x = 2

x^{3} + x^{2} + \frac{6}{x}

What is the derivative of (6e^w)/(7w) ?
The derivative of (6e^w)/(7w) is (6(e^ww-e^w))/(7w^2)
What is the first derivative of (6e^w)/(7w) ?
The first derivative of (6e^w)/(7w) is (6(e^ww-e^w))/(7w^2)