What is the integral of (x^2-1)cos(x) ?

The integral of (x^2-1)cos(x) is x^2sin(x)+2xcos(x)-3sin(x)+C

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integral of (x^2-1)cos(x)

\int (x^{2} - 1) cos (x) d x

x^{2} sin (x) + 2 x cos (x) - 3 sin (x) + C

Solution steps

\int (x^{2} - 1) cos (x) d x

Expand

(x^{2} - 1) cos (x) : x^{2} cos (x) - cos (x)

= \int x^{2} cos (x) - cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} cos (x) d x - \int cos (x) d x

\int x^{2} cos (x) d x = x^{2} sin (x) - 2 (- x cos (x) + sin (x))

\int cos (x) d x = sin (x)

= x^{2} sin (x) - 2 (- x cos (x) + sin (x)) - sin (x)

Simplify

x^{2} sin (x) - 2 (- x cos (x) + sin (x)) - sin (x) : x^{2} sin (x) + 2 x cos (x) - 3 sin (x)

= x^{2} sin (x) + 2 x cos (x) - 3 sin (x)

Add a constant to the solution

= x^{2} sin (x) + 2 x cos (x) - 3 sin (x) + C

\int \frac{- 2 x}{x ^{2} - 4} d x

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\int (6 + x^{4}) (7 - x^{3}) d x

\int x f (1 - x^{2}) d x

\int \frac{e ^{x}}{2 - e ^{x}} d x

What is the integral of (x^2-1)cos(x) ?
The integral of (x^2-1)cos(x) is x^2sin(x)+2xcos(x)-3sin(x)+C