What is the integral of cos(y)+ycos(x) ?

The integral of cos(y)+ycos(x) is cos(y)x+ysin(x)+C

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integral of cos(y)+ycos(x)

\int cos (y) + y cos (x) d x

cos (y) x + y sin (x) + C

Solution steps

\int cos (y) + y cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (y) d x + \int cos (x) y d x

\int cos (y) d x = cos (y) x

\int cos (x) y d x = y sin (x)

= cos (y) x + y sin (x)

Add a constant to the solution

= cos (y) x + y sin (x) + C

\int 190 - 8 x d x

\int (2 x - 2)^{2} d x

\int \frac{1 + ln ( x )}{x ln ( x ^{2} )} d x

\int \frac{x}{x ^{2} + 2 x - 3} d x

\int (\frac{y ^{5}}{b} + a)^{\frac{7}{8}} y^{4} d y

What is the integral of cos(y)+ycos(x) ?
The integral of cos(y)+ycos(x) is cos(y)x+ysin(x)+C