What is the integral of (x^2)/((1+x^2)^{5/2)} ?

The integral of (x^2)/((1+x^2)^{5/2)} is (x^3)/(3(1+x^2)^{3/2)}+C

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integral of (x^2)/((1+x^2)^{5/2)}

\int \frac{x ^{2}}{( 1 + x ^{2} ) ^{\frac{5}{2}}} d x

\frac{x ^{3}}{3 ( 1 + x ^{2} ) ^{\frac{3}{2}}} + C

Solution steps

\int \frac{x ^{2}}{( 1 + x ^{2} ) ^{\frac{5}{2}}} d x

Apply Trigonometric Substitution

: \int cos^{3} (u) tan^{2} (u) d u

= \int cos^{3} (u) tan^{2} (u) d u

Rewrite using trig identities

= \int sin^{2} (u) cos (u) d u

Apply u-substitution

: \int v^{2} d v

= \int v^{2} d v

Apply the Power Rule

: \frac{v ^{3}}{3}

= \frac{v ^{3}}{3}

Substitute back

= \frac{sin ^{3} ( arctan ( x ) )}{3}

Simplify

\frac{sin ^{3} ( arctan ( x ) )}{3} : \frac{x ^{3}}{3 ( 1 + x ^{2} ) ^{\frac{3}{2}}}

= \frac{x ^{3}}{3 ( 1 + x ^{2} ) ^{\frac{3}{2}}}

Add a constant to the solution

= \frac{x ^{3}}{3 ( 1 + x ^{2} ) ^{\frac{3}{2}}} + C

\int \frac{1}{a + e ^{a x}} d x

\int \frac{2 x ^{2} - 5}{x} d x

\int (3 x + 5)^{5} d x

\int \frac{3 x ^{3} + 2 x ^{2} + 3 x + 3}{x ^{2} + 1} d x

\int \frac{x - 2}{x ^{2} + x ^{4}} d x

What is the integral of (x^2)/((1+x^2)^{5/2)} ?
The integral of (x^2)/((1+x^2)^{5/2)} is (x^3)/(3(1+x^2)^{3/2)}+C