What is the integral of (21x^2-12x-5) ?

The integral of (21x^2-12x-5) is 7x^3-6x^2-5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (21x^2-12x-5)

\int (21 x^{2} - 12 x - 5) d x

7 x^{3} - 6 x^{2} - 5 x + C

Solution steps

\int 21 x^{2} - 12 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 21 x^{2} d x - \int 12 x d x - \int 5 d x

\int 21 x^{2} d x = 7 x^{3}

\int 12 x d x = 6 x^{2}

\int 5 d x = 5 x

= 7 x^{3} - 6 x^{2} - 5 x

Add a constant to the solution

= 7 x^{3} - 6 x^{2} - 5 x + C

\int (x^{4} + 3) (3 + 2 x) d x

\int y^{10} d y

\int 8 - 2 x^{2} d x

\int \frac{e ^{x}}{( e ^{x} + 1 ) ^{6}} d x

\int \frac{- 3 x ^{5} - 2 x ^{3} + 4}{3 x ^{4} + x ^{2}} d x

What is the integral of (21x^2-12x-5) ?
The integral of (21x^2-12x-5) is 7x^3-6x^2-5x+C