What is the integral of ln(x)x^{-2} ?

The integral of ln(x)x^{-2} is -(ln(x))/x-1/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ln(x)x^{-2}

\int ln (x) x^{- 2} d x

- \frac{ln ( x )}{x} - \frac{1}{x} + C

Solution steps

\int ln (x) x^{- 2} d x

Apply Integration By Parts

: - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

= - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

\int - \frac{1}{x ^{2}} d x = \frac{1}{x}

= - \frac{ln ( x )}{x} - \frac{1}{x}

Add a constant to the solution

= - \frac{ln ( x )}{x} - \frac{1}{x} + C

\int \frac{x ^{2} - 4}{x ^{2} + 4} d x

\int \frac{4}{( x - 9 ) ( x - 5 )} d x

\frac{5}{x}

\int 5 x e^{8 x^{2}} d x

\int e^{x^{7}} x^{6} d x

What is the integral of ln(x)x^{-2} ?
The integral of ln(x)x^{-2} is -(ln(x))/x-1/x+C